Joseph jogs from one end A to the other end B of a straight 300m road in 2 minutes 30 second and then turns around and jogs 100m back to point C in another 1 minute. What are Joseph’s average speeds and velocities in jogging from
a) A to B
b) A to C?
Answers
Answer:
Velocity = dispacement / time
Speed = distance / time
a) when he jogs from A to B on a straight road,
displacement = distance = 300m
time = 2 minutes 30 seconds = 150 s
velocity = 300/150 = 2 m/s
speed = 300/150 = 2m/s
b)when he jogs from A to B and turns back to C,
displacement = 300-100 = 200m
distance = 300+100 = 400m
time = 3 minute 30 second = 210 s
velocity = 200/210 = 20/21 m/s
speed = 400/210 = 40/21 m/s
Answer:
Hello mate!!
Here is your answer.!
⬇️
(a) Distance covered A➡️B = 300m; S=300m
★ Time taken = 2 min 50 sec
=( 2×60 +50 )
= 120+50
= 170 seconds .
★Average speed = Total distance/Total time
= 300 m / 170 s
= 30 / 17
= 1.76 ms-¹.
★Average velocity = Displacement / Total time
= 300 m / 170 s
= 1.76 ms-¹.
(b) From A➡️C
★ Total distance = A to B + B to C
= 300 +100
= 400 m
★Total time = 170+60
= 230 seconds.
★Average speed = 400 / 230
= 40 / 23
= 1.74 ms-¹.
★Average velocity = 200 / 230
= 20 / 30
= 0.87 m/s