.Joseph jogs from one end A to the other end B of a
straight 300 m road in 2 minutes 50 seconds and
then turns around and jogs 100 m back to point C
in another 1 minute. What are Joseph's average
speeds and velocities in jogging (a) from A to B and
(b) from A to C?
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Answered by
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Answer:
Explanation:
A to B
Speed = distance / time
= 300 / 170
=1.764 m/s
A to C
Speed = distance / time
= 200 / 110
= 1.81 m/s
Hope it helps
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