Physics, asked by veenak448, 10 months ago

.Joseph jogs from one end A to the other end B of a
straight 300 m road in 2 minutes 50 seconds and
then turns around and jogs 100 m back to point C
in another 1 minute. What are Joseph's average
speeds and velocities in jogging (a) from A to B and
(b) from A to C?​

Answers

Answered by batradanish62
5

Answer:

please mark it as brainlist answer

Attachments:
Answered by aneeshmishra108
3

Answer:

Explanation:

A to B

Speed = distance / time

          = 300 / 170

          =1.764 m/s

A to C

Speed = distance / time

           = 200 / 110

           = 1.81 m/s

Hope it helps

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