Question

just trying this

$\displaystyle\lim_{x\to\infty}\frac{3x}{x+2}$​

Answer 1

$limit \: x \: tends \: to \: \infty \: \frac{3x}{x + 2} \\ \\limit \: x \: tends \: to \: \infty \: \frac{3x}{x(1 + \frac{2}{x} )} \\ \\ \frac{3}{1 + \frac{2}{ \infty } } \\ \\ \frac{3}{1} \\ \\ 3$