(K-1)xsquare+kx+1is3find k
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Hi friend,
given one of the zeros of quadratic polynomial (k-1)x2+kx+1 is -3
so when we substitute -3 in the polynomial ,we get 0
→(k-1)(-3)²+k(-3)+1=0
→9k-9-3k+1=0
→6k-8=0
→k=8/6=4/3
I hope this will help u ;)
please mark as the brainlist answer
thank you.♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️
given one of the zeros of quadratic polynomial (k-1)x2+kx+1 is -3
so when we substitute -3 in the polynomial ,we get 0
→(k-1)(-3)²+k(-3)+1=0
→9k-9-3k+1=0
→6k-8=0
→k=8/6=4/3
I hope this will help u ;)
please mark as the brainlist answer
thank you.♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️
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