Kabir invested rs 50000 in mf on 5 march 2011 with nav of 560 he redeemed units on 18 October 2011 when nav was 650 there was no entry or exit load find the number of unit purchased total gain and rate of return
Answers
Answer:
Answer :
Acceleration of the object, a = 2.5 m/s²
Velocity of the object after 10 seconds, v = 25 m/s
Amount of work done by the body, W = 625 J
Explanation :
Given :
Mass of the object, m = 2 kg
Force acting on the object, F = 5 N
Time of contact of force, t = 10 s
Initial velocity of the object, u = 0 m/s
[Initial velocity is taken as zero because the object is starting from rest]
To find :
Acceleration of the object, a = ?
Velocity of the object after 10 seconds,i v = ?
Amount of work done by the body, W = ?
Knowledge required :
Formula for force applied by a body :
⠀⠀⠀⠀⠀⠀⠀⠀⠀F = ma⠀
⠀[Where : F = Force applied by the body, m = Mass of the body, a = Acceleration produced by the body]
First equation of motion :
⠀⠀⠀⠀⠀⠀⠀⠀⠀v = u + at⠀
⠀[Where : v = Final Velocity of the body, u = Initial velocity of the body, a = Acceleration produced by the body, t = Time taken]
Second equation of motion :
⠀⠀⠀⠀⠀⠀⠀⠀⠀s = ut + ½at²⠀
⠀[Where : s = Distance traveled by the body, u = Initial velocity of the body, a = Acceleration produced by the body, t = Time taken]
Formula for work done by a body ;
⠀⠀⠀⠀⠀⠀⠀⠀⠀W = F s⠀
⠀[Where : W = Work done of the body, F = Force applied on the body, s = Displacement of the body]
Solution :
To find out the acceleration produced by the body :
⠀By using the equation for force and substituting the values in it, we get :
⠀⠀=> F = ma
⠀⠀=> 5 = 2 × a
⠀⠀=> 5/2 = a
⠀⠀=> 2.5 = a
⠀⠀⠀⠀⠀∴ a = 2.5 m/s²
Hence the accelaration produced by the body is 2.5 m/s².
To find out the velocity of the body after 10 s :
⠀By using the first equation of motion and substituting the values in it, we get :
⠀⠀=> v = u + at
⠀⠀=> v = 0 + 2.5 × 10
⠀⠀=> v = 25
⠀⠀⠀⠀⠀∴ v = 25 m/s
Hence the velocity of the body after 10 s is 25 m/s.
To find out the displacement the body :
⠀By using the second equation of motion and substituting the values in it, we get :
⠀⠀=> s = ut + ½at²
⠀⠀=> s = (0)10 + ½ × 2.5 × 10²
⠀⠀=> s = ½ × 2.5 × 100
⠀⠀=> s = 125
⠀⠀⠀⠀⠀∴ s = 125 m
Hence the displacement of the body is 125 m.
To find out the work done by the body :
⠀By using the formula for work done on a body and substituting the values in it, we get :
⠀⠀=> W = F s
⠀⠀=> W = 5 × 125
⠀⠀=> W = 625
⠀⠀⠀⠀⠀∴ W = 625 J
Hence the work done by the body is 625 J.
Answer:
Answer :
Acceleration of the object, a = 2.5 m/s²
Velocity of the object after 10 seconds, v = 25 m/s
Amount of work done by the body, W = 625 J
Explanation :
Given :
Mass of the object, m = 2 kg
Force acting on the object, F = 5 N
Time of contact of force, t = 10 s
Initial velocity of the object, u = 0 m/s
[Initial velocity is taken as zero because the object is starting from rest]
To find :
Acceleration of the object, a = ?
Velocity of the object after 10 seconds,i v = ?
Amount of work done by the body, W = ?
Knowledge required :
Formula for force applied by a body :
⠀⠀⠀⠀⠀⠀⠀⠀⠀F = ma⠀
⠀[Where : F = Force applied by the body, m = Mass of the body, a = Acceleration produced by the body]
First equation of motion :
⠀⠀⠀⠀⠀⠀⠀⠀⠀v = u + at⠀
⠀[Where : v = Final Velocity of the body, u = Initial velocity of the body, a = Acceleration produced by the body, t = Time taken]
Second equation of motion :
⠀⠀⠀⠀⠀⠀⠀⠀⠀s = ut + ½at²⠀
⠀[Where : s = Distance traveled by the body, u = Initial velocity of the body, a = Acceleration produced by the body, t = Time taken]
Formula for work done by a body ;
⠀⠀⠀⠀⠀⠀⠀⠀⠀W = F s⠀
⠀[Where : W = Work done of the body, F = Force applied on the body, s = Displacement of the body]
Solution :
To find out the acceleration produced by the body :
⠀By using the equation for force and substituting the values in it, we get :
⠀⠀=> F = ma
⠀⠀=> 5 = 2 × a
⠀⠀=> 5/2 = a
⠀⠀=> 2.5 = a
⠀⠀⠀⠀⠀∴ a = 2.5 m/s²
Hence the accelaration produced by the body is 2.5 m/s².
To find out the velocity of the body after 10 s :
⠀By using the first equation of motion and substituting the values in it, we get :
⠀⠀=> v = u + at
⠀⠀=> v = 0 + 2.5 × 10
⠀⠀=> v = 25
⠀⠀⠀⠀⠀∴ v = 25 m/s
Hence the velocity of the body after 10 s is 25 m/s.
To find out the displacement the body :
⠀By using the second equation of motion and substituting the values in it, we get :
⠀⠀=> s = ut + ½at²
⠀⠀=> s = (0)10 + ½ × 2.5 × 10²
⠀⠀=> s = ½ × 2.5 × 100
⠀⠀=> s = 125
⠀⠀⠀⠀⠀∴ s = 125 m
Hence the displacement of the body is 125 m.
To find out the work done by the body :
⠀By using the formula for work done on a body and substituting the values in it, we get :
⠀⠀=> W = F s
⠀⠀=> W = 5 × 125
⠀⠀=> W = 625
⠀⠀⠀⠀⠀∴ W = 625 J
Hence the work done by the body is 625 J.