Kabir sold a watch at a loss of 6/2/3%. Had he sold it for ₹220 more,he would have made a profit of 8%. Find the cost price of the watch. this answer is 1500
please solve d the question
Answers
Answer:
The cost price of watch is 1500 ₹
Explain tion
As given in the question that kabir sold a watch a loss of 6\frac{2}{3}\%6
3
2
% .
If he sold it for 220 more. He would have made a profit of 8%.
We have to find the cost price of watch.
Let the selling price of watch is x.
We know that,
S.P. = \frac{100\ -\ loss\%}{100}\times C.P.S.P.=
100
100 − loss%
×C.P.
x = \frac{100\ -\ \frac{20}{3} }{100}\times C.P.x=
100
100 −
3
20
×C.P.
x = \frac{\frac{300\ -\ 20}{3} }{100}\times C.P.x=
100
3
300 − 20
×C.P.
x = \frac{280}{3}\times\frac{1}{100} \times C.P.x=
3
280
×
100
1
×C.P.
x = \frac{14}{15}\times C.P.x=
15
14
×C.P.
When he sold it for 220 more:
S.P. = \frac{100\ +\ gain\%}{100}\times C.P.S.P.=
100
100 + gain%
×C.P.
x\ +\ 220 = \frac{100\ +\ 8}{100}\times C.P.x + 220=
100
100 + 8
×C.P.
\frac{14}{15}\times C.P.\ +\ 220 = \frac{108}{100}\times C.P.
15
14
×C.P. + 220=
100
108
×C.P.
\frac{14}{15}\times C.P.\ +\ 220 = \frac{27}{25}\times C.P.
15
14
×C.P. + 220=
25
27
×C.P.
220 = \frac{27}{25}\times C.P.\ -\ \frac{14}{15}\times C.P.220=
25
27
×C.P. −
15
14
×C.P.
220 = (\frac{27}{25}\ -\ \frac{14}{15})\times C.P.220=(
25
27
−
15
14
)×C.P.
220 = (\frac{81\ -\ 70}{75})\times C.P.220=(
75
81 − 70
)×C.P.
220 = (\frac{11}{75})\times C.P.220=(
75
11
)×C.P.
220\times\frac{75}{11} = C.P.220×
11
75
=C.P.
20 x 75 = C.P.
∴ C.P. = 1500 Rs.
Hence, the cost price of watch will be 1500 Rs.
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