Kalayan's present age is one-third his mother's present age.If the mother's age was five times his age 6 years ago,what are their present ages
Answers
Answer:
Kalyan's present age= 12
Kalyan's mother's present age= 36
Step-by-step explanation:
Let Kalyan's present age= x and Kalyan's mother's present age= y
Currently, y= 3x -Equation 1
6 years ago= y-6= 5(x-6)
= y-6= 5x-30 -Equation 2
From the Equations 1 and 2, we can say that:
3x-6= 5x-30
--> 3x-5x= -30+6
--> -2x= -24
--> 2x= 24
--> x= 12 - Equation 3
From Equations 1 and 3, we can say that:
y= 3(12)
--> y= 36
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Answer:
At present mother's age =x yrs
Kalayan's age= x/3 years
6 years ago
Mother's age=(x-6) years
Kalayan's age = (x/3 - 6) years
Given
5(x/3 -6)=(x-6)
5(x-18)/3=(x-6)
5x-90=3(x-6)
5x-90=3x-18
5x-3x=90-18
2x=72
x=72/2
x=36
Therefore, at present mother's age=x=36 years Kalayan's age =x/3=36/3=12 years.
Hope this helps you.