Math, asked by tamannadhiman49, 3 months ago

Kalayan's present age is one-third his mother's present age.If the mother's age was five times his age 6 years ago,what are their present ages​

Answers

Answered by aadimalhotra0802
1

Answer:

Kalyan's present age= 12

Kalyan's mother's present age= 36

Step-by-step explanation:

Let Kalyan's present age= x and Kalyan's mother's present age= y

Currently, y= 3x                                                                -Equation 1

6 years ago= y-6= 5(x-6)

                   = y-6= 5x-30                                                 -Equation 2

From the Equations 1 and 2, we can say that:

3x-6= 5x-30

--> 3x-5x= -30+6

--> -2x= -24

--> 2x= 24

--> x= 12                                                                             - Equation 3

From Equations 1 and 3, we can say that:

y= 3(12)

--> y= 36

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Answered by harshithsivakumar1
0

Answer:

At present mother's age =x yrs

Kalayan's age= x/3 years

6 years ago

Mother's age=(x-6) years

Kalayan's age = (x/3 - 6) years

Given

5(x/3 -6)=(x-6)

5(x-18)/3=(x-6)

5x-90=3(x-6)

5x-90=3x-18

5x-3x=90-18

2x=72

x=72/2

x=36

Therefore,  at present  mother's age=x=36 years  Kalayan's age =x/3=36/3=12 years.

Hope this helps you.

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