kindly help
chapter-expansions
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JMK1:
thanks
btw,is this a formula?
i dont know abt it
yaa this is it is given in r.s.agarwall
ok thanx
my pleasure
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⭐⭐Hello friend..Ur answer is here⤵⤵
⚫ 3a+5b+4c=0
Applying the formula...
As we know that➡ If a+b+c=0 then a^3+b^3+c^3=3abc
Now we take..
➡(3a+5b+4c)^3=0
➡Here 3a+5b+4c=0 then (3a)^3+(5b)^3+(4c)^3=3×3a×5b×4c
➡27a^3+125b^3+64c^3=180abc HENCE PROVED
I HOPE IT IS HELPFUL TO YOU☺
⚫ 3a+5b+4c=0
Applying the formula...
As we know that➡ If a+b+c=0 then a^3+b^3+c^3=3abc
Now we take..
➡(3a+5b+4c)^3=0
➡Here 3a+5b+4c=0 then (3a)^3+(5b)^3+(4c)^3=3×3a×5b×4c
➡27a^3+125b^3+64c^3=180abc HENCE PROVED
I HOPE IT IS HELPFUL TO YOU☺
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