Question

koi pls solve this....!
A spring weighing machine inside a stationary lift reads 50 kg when a man stands on it. What would happen
to the scale reading if the lift is moving upward with (1) constant velocity, and (ii) constant acceleration
​

Answer 1

Answer:

(1) 50kg i. e remain same

(2) when lift move up with constant acc. then net acc. will become (g+a) hence reading will increase since now

T=m(g+a)

Answer 2

Hey...dii.. here is yur ans...

______________________

1) In the case of constant velocity of lift, there is no fictitious force; therefore the apparent weight = actual wieght. Hence the reading of machine is 50 kgwt.

2) In this case the acceleration is upward, the fictitious force R = ma acts downward, therefore apparent weight is more than actual weight that is W' = W + R = m (g+a).

Hence scale shows a reading = m (g+a) = mg [1+a/g]

N=[50+50a/g] kgwt.

Hope it helps u✌