Question

koi sovle kar doo I wanna know the solution

Answer 1

Given
$f(x) = {x}^{2} - px + q \\ and \: \alpha \: and \: \beta are \: roots \: of \: the \: equation \\ hence \: \alpha + \beta = - \frac{b}{a} = \frac{p}{1} \\ \alpha \beta = \frac{c}{a} = q \\ now \: { \alpha }^{2} + { \beta }^{2} = {( \alpha + \beta) }^{2} - 2 \alpha \beta \\ = {p}^{2} - 2q \\ now \: \frac{1}{ \alpha } + \frac{1}{ \beta } = \frac{ \alpha + \beta }{ \alpha \beta } = \frac{p}{q}$