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B is 4/3 times as efficient as A. If A can complete 5/8 of a given task in 15 days, what fraction of the same task would remain incomplete if B work on it independently for 10 days only?
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Part of the work done by A in 15days =5/8
Part of the work done by A in 1day=
5/(8×15)
=1/24
Since B is 4/3 times efficient as A
Part of the work done by B in 1day=
(4/3)×(1/24)
=1/18
Part of the work done by B in 10days=
10×1/18
=5/9
The part of the task left after B working for 10 days only=1-(5/9)
=4/9
HOPE THIS HELPS!!!!!!!
Part of the work done by A in 1day=
5/(8×15)
=1/24
Since B is 4/3 times efficient as A
Part of the work done by B in 1day=
(4/3)×(1/24)
=1/18
Part of the work done by B in 10days=
10×1/18
=5/9
The part of the task left after B working for 10 days only=1-(5/9)
=4/9
HOPE THIS HELPS!!!!!!!
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