Question

kx + 3y = 3; 12x + ky = 6 has no solution.
find the value of k for the given system of linear equations satisfying the condition below ​

Answer 1

Answer:

there is no common solution

therefore lines must be parallel

kx+3y=3_________________1

12x+ky=6_________________2

equation doesn't have common solutions

that means

a1/a2= b1/b2 is not equal to c1/c2

k/12=3/k

k^2=36

k=6

Answer 2

Answer:

Step-by-step explanation:

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