Question

(l+m)²-(l-m)²
factorize​

Answer 1

Step-by-step explanation:

(l+m)² - (l-m)²

= (l+m+l-m)(l+m-(l-m))

= 2l×2m

= 4lm

Answer 2

$\LARGE\mathfrak{\underline\textcolor{aqua}{✯\; Solution :-}}$

$\large\textsf{ }$

• Assume ( 1 + m )² as a and ( 1 - m )² as b :-
• By using the formula a² - b² = ( a + b )( a - b )

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{( 1 + m )² - ( 1 - m )²}$

$\qquad\tt{:}\longrightarrow\large\textsf{[ ( 1 + m ) + ( 1 - m ) ] × [ ( 1 + m ) - ( 1 - m ) ]}$

$\qquad\tt{:}\longrightarrow\large\textsf{( 1 + m + 1 - m ) × ( 1 + m - 1 + m ) }$

$\qquad\tt{:}\longrightarrow\large\textsf{( 1 + 1 + m - m ) × ( 1 - 1 + m + m )}$

$\qquad\tt{:}\longrightarrow\large\textsf{2 × 2m}$

$\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{red}{4m}}$

$\large\textsf{ }$

$\LARGE\mathfrak{\underline\textcolor{aqua}{✯\; More \; \; Formula :-}}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{( a + b )² = a² + b² + 2ab}$

$\qquad\tt{:}\longrightarrow\large\textsf{( a - b )² = a² + b² - 2ab}$

$\qquad\tt{:}\longrightarrow\large\textsf{a² - b² = ( a + b ) ( a - b )}$

$\qquad\tt{:}\longrightarrow\large\textsf{a² + b² = ( a + b )² - 2ab}$

$\qquad\tt{:}\longrightarrow\large\textsf{a³ + b³ = ( a + b ) ( a² - 2ab + b² )}$

$\qquad\tt{:}\longrightarrow\large\textsf{a³ - b³ = ( a - b ) ( a² + ab + b² )}$

$\qquad\tt{:}\longrightarrow\large\textsf{( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ac }$

$\large\textsf{ }$

$\large\textsf\textcolor{purple}{ \; \; \; \; \; \; \; \; \; \; \; \; ◈ ━━━━━━━ ✪ ━━━━━━━ ◈}$

$\LARGE\mathcal\fcolorbox{black}{red}{Thanks :)}$