Question

Ladder 25m long reaches a window of building 20 m above the ground the distance of the foot of the ladder from the building

Answer 1

hope this will help you out

Answer 2

$\bigstar\bf\underline{\underline{Given:-}}$

A ladder "25 m" long

Reaches a window of a building "20 m" about the ground

$\bigstar\bf\underline{\underline{To \ find:-}}$

The distance of foot of ladder from the building.

$\bigstar\bf\underline{\underline{Answer:-}}$

Let AC be the ladder and A be the position of the window

Then,

AC = 25 m , AB = 20 m

By using Pythagoras theorem,

∴ AB² = AC² + BC²

$\implies\displaystyle{(25 m)^2 = (20 m)^2 + BC^2}$

$\implies\displaystyle{BC^2 = 625 m^2 - 400 m^2}$

$\implies\displaystyle{BC^2 = 225 m^2}$

$\implies\displaystyle{BC^2 = (15 m)^2}$

(Here, both square's gets cancelled)

$\implies\boxed{\boxed{\underline{\bf\red{BC = 15 cm}}}}$

Therefore, the distance of the foot of ladder from the building is "15 cm"