Question

Latent heat of vaporisation of a liquid at
400 K at 1 atm pressure is 20 kcal/mol. If we
take 2 moles of this liquid at same
temperature and pressure, the change in
internal energy will be
(a) 27.0 kcal
(b) 16 kcal
(c) 38.4 kcal
(d) 17 kcal
​

Answer 1

Answer:

3A(l)⟶3A(g)

△n=3−0=3

△E=△H−△nRT

=3×10−3×500×0.002

=27kcal

Explanation:

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