Question

Lead spheres of diameter 6 cm each are dropped into a cylindrical beaker containing some water and are fully submerged. If the diameter of the beaker is 18 cm and water level rises by 40 cm, find the number of lead spheres dropped in the water.

Answer 1

V1= 4/3π(6)³
V2=π(9)²×40
V2/V1 = no. of balls
= (9×9×40)÷(4×2×6×6)
= 3240/288= 11.25=11(approx)
= no.of balls

Answer 2

Answer:

Step-by-step explanation:HI friend,here is ur answer...

D1=6cm⟹r1D2=18cm⟹r2h=3cm=9cm=40cm

n43πr31=πr22h

∴n=r22h(43)r31

n=9×9×40×34×3×3×3=90

∴n=90 lead shots

HOPE IT HELPS U...

U CAN ALSO TRY THIS QUESTION OUT...THIS QN IS IMPORTANT...

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