Lead spheres of diameter 6 cm each are dropped into a cylindrical beaker containing some water and are fully submerged. If the diameter of the beaker is 18 cm and water level rises by 40 cm, find the number of lead spheres dropped in the water.
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Answered by
30
V1= 4/3π(6)³
V2=π(9)²×40
V2/V1 = no. of balls
= (9×9×40)÷(4×2×6×6)
= 3240/288= 11.25=11(approx)
= no.of balls
V2=π(9)²×40
V2/V1 = no. of balls
= (9×9×40)÷(4×2×6×6)
= 3240/288= 11.25=11(approx)
= no.of balls
Answered by
29
Answer:
Step-by-step explanation:HI friend,here is ur answer...
D1=6cm⟹r1D2=18cm⟹r2h=3cm=9cm=40cm
n43πr31=πr22h
∴n=r22h(43)r31
n=9×9×40×34×3×3×3=90
∴n=90 lead shots
HOPE IT HELPS U...
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