lens forms an image of an object placed at a distance of 16 cm from it, at
a distance 48 cm in front of it . Find:
(i) the focal length
(ii) the nature of the image.
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Answered by
1
Answer:
ANSWER
When object is kept 16 cm away,
v
1
1
−
(−16)
1
=
f
1
............ (1)
Magnification=
(−16)
v
1
When object is kept 6 cm away,
v
2
1
−
(−6)
1
=
f
1
................ (2)
Magnification=
−6
v
2
Since the sizes of the images is same, M
1
=−M
2
Hence, v
2
=
8
3v
1
Using this relation in Equation 1 and Equation 2, we get
f=11cm
Explanation:
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0
Answer:
......................c
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