Question

Let A = {1, 2, 3} and B = {5, 7}. Then possible number of relation from A to B?

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Answer 1

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 ➺..Given, A = {1,2,3} and B = {5,7}

Number of elements in set A = n(A)=3

Number of elements in set B = n(B)=2

No. of relations from A to B= 2^{n(A)×n(B)}

=2^{3×2}

=2^{6}

=64 «Ans»

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☆✿╬ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs ᴜ╬✿☆

$\large{\dag{\purple{\bold{HIT_LIKE}}}}$

$\large{\leadsto{\orange{\bold{Brainliest}}}}$

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Answer 2

SOLUTION

GIVEN

A = {1, 2, 3} and B = {5, 7}

TO DETERMINE

The number of possible number of relation from A to B

CONCEPT TO BE IMPLEMENTED

Cartesian Product :

Let A and B are two sets. Then the Cartesian product of A and B is denoted by A × B and defined as

$\sf{A \times B = \{(x, y) : x \in A \: \: and \: \: y \in B \}}$

Relation :

Let A and B are two non empty sets. Then a Relation R from A to B is a Subset of A × B

EVALUATION

Here it is given that

A = {1, 2, 3} and B = {5, 7}.

So we have

n(A) = 3 , n(B) = 2

We know that the number of subsets of a set having n elements

$\sf = {2}^{n}$

Hence the required number of possible number of relation from A to B

$\sf = {2}^{3 \times 2}$

$\sf = {2}^{6}$

$\bf = 64$

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