Question

Let A, B, C be there events in a probability space. Suppose that P(A)= 0.5, and P(B)= 0.3, P(C)=
0.2, P(A∩B)= 0.15, P(A∩C)= 0.1 and P(B∩C)= 0.06.
The smallest possible value of P(Ac ∩B c∩ C
c
) is

Answer 1

Answer:

0.69

Step-by-step explanation:

P(A∩B∩C)

= P(A) + P(B) + P(C) - P(A∩B) -P(B∩C) - P(A∩C)

put the values you'll get rhe answer

Answer 2

Answer:

Let A, B, C be there events in a probability space. suppose that P(ANC) =0.1 and p(c) =0.06. The smallest possible value of P(AcnBcnC (c) is ___