Let A can do a particular task in 25 days and B can do it in 20 days if they work individually,
They work together for 5 days and then B leaves. In how many days will A finish the
remaining task?
by A
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As A and B do same work
LCM (20,25)=100
Let say A and B do 100 work
Per day work of B=100/20=5
Per day work of A=100/25=4
Per day work if B and A both work together=5+4=9
Both together worked for 5 days.
Therefore work completed in 5 days=5×9=45
Now work which is left =100–45=55
As B left the work after 5 days ,A alone will work to complete 55 work
Per day work of A ×days = 55
days =55/4
days=13 3/4
Therefore total work will be completed by
5+13 3/4=18 and 3/4 days
Answer is 18 3/4
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