Let ABC be a right triangle in which AB = 6 cm, BC = 8 cm and angle B = 90 digress. BD is perpendicular form B on AC. The circle through B, C, D is drawn. construct the tangents from A to this circle
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Heya,
Here is your answer.......
• Draw a line segment AB = 6 cm.
• Draw a right angle at B and then, BC = 8cm.
• Now,
Draw perpendicular BD to AC.
• We know in a right triangle , hypotenuse is the Diameter of circum circle.
• Considering BC as diameter ,draw a circle passing through points B, C and D.
• Join A to O and taking AO as diameter ,draw second circle.
• From point A draw tangents AB and AP.
Then,
You get your figure !!✌
IF IT'S HELPFUL PLEASE MARK IT BRAINLIEST ❤
Here is your answer.......
• Draw a line segment AB = 6 cm.
• Draw a right angle at B and then, BC = 8cm.
• Now,
Draw perpendicular BD to AC.
• We know in a right triangle , hypotenuse is the Diameter of circum circle.
• Considering BC as diameter ,draw a circle passing through points B, C and D.
• Join A to O and taking AO as diameter ,draw second circle.
• From point A draw tangents AB and AP.
Then,
You get your figure !!✌
IF IT'S HELPFUL PLEASE MARK IT BRAINLIEST ❤
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