Question

Let ABC be a right triangle in which AB-8cm and angleB-90°.BD is the perpendicular from B on AC. The circle through B,C,D is drawn.Construct the tangents from A to this circle

Answer 1

☺HEY!!!!☺

↙↙⭐Here ur answer⭐ ↙↙

Steps of construction:

1. Draw a line segment BC = 8 cm.

2. Make a right angle at the point B i.e., ∠CBX = 90°

3. Draw a are of radius 6 cm as centre B which intersect BX at the point A. 4. Join AC so, ABC is required right angle triangle.

5. Draw a arc taking centre B which intersect AC at the point K and L respectively taking K and L centre draw two arcs of same radius which intersect at the point M.

6. Join BM so, ∠BDC = 90°

7. Draw perpendicular bisector of BC.

8. Draw a circle taking radius equal to OB and centre O which passes through B, D and C.

9. Draw a arc taking centre A and radius equal to AB intersect the circle at point P so AP is the tangents.

And fig in this attachment

⤴⤴☺⭐Hope its may help uu⤴⤴☺⭐