Question

let ABCD be a square of side 2a . find the coordinates of the vertices of this square when the centre of the square is at the origin and coordinates axes are parallel to the sides AB and AD respectively. ( please draw the diagram according to the question)

Answer 1

As centre of square is at origin,

A in 3rd quadrant , B in 4th quadrant , C in first quadrant , D in 2nd quadrant

A( - a, -a ) , B ( a , -a ) , C ( a , a ) , D ( -a , a)

Answer 2

Here is your answer.......

ABCD be a square

Side = 2a 
Centre = (0,0)  Origin

Y-coordinates of AB = (0-2a)/2 = -a
Y-coordinates of AD = (0+2a)/2 = a

∴ the coordinates are :-
A(-a,-a)
B (a,-a)
C (a,a)
D (-a,a)

#Refer to the figure.

I hope it helps you ^_^