let ABCD be a trapezium in which AB||CD and let E is the midpoint of AD.If G is a point on BC such that EG||DC.prove that EG=1/2(AB+DC)
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Answer:
I ll show it through an attachment
Step-by-step explanation:
it is a tricky diagram but this is the correct one.
we have,
AB//CD
but CD//EG (given)
EG//AB then GM//AB
In triangle ABC, GM//AB and G is the mid point of AC. then M is the mid point of AC (THEOREM:THE LINE DRAWN THROUGH THE MID POINT OF ONE SIDE OF A ∆ // TO ANOTHER SIDE BISECTS THE THIRD SIDE)
GM=1/2 AB --------1
(THEOREM: THE line joining the mid point of two sides of ∆ is // to the third side and is 1/2 of its length)
Similarly in triangle ABD
EM= 1/2 CD-------2
Adding 1 and 2
GM+ EM=1/2 AB+1/2 CD
EG=1/2(AB+CD)
HENCE PROVED.
HOPE THIS HELP YOU.
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