Let C be any point lying on the line segment AB joining the point A(1,1), B(2,-3) such that 3AC = CB . Find the coordinate of C.
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Answered by
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HELLO DEAR,
3AC=CB
or, AC/CB=1/3
If we denote the coordinate of C by (x,y) then
x=(mx₂+nx₁)/(m+n)
y=(my₂+ny₁)/(m+n)
Here,
(x₁,y₁)=(1,1), (x₂,y₂)=(2,-3) and m:n=1:3
, x=(1×2+3×1)/(1+3)
=(2+3)/4
=5/4
y=(1×-3+3×1)/(1+3)
=(-3+3)/4
=0
, coordinate of C is (5/4,0)
I HOPE ITS HELP YOU DEAR,
THANKS
3AC=CB
or, AC/CB=1/3
If we denote the coordinate of C by (x,y) then
x=(mx₂+nx₁)/(m+n)
y=(my₂+ny₁)/(m+n)
Here,
(x₁,y₁)=(1,1), (x₂,y₂)=(2,-3) and m:n=1:3
, x=(1×2+3×1)/(1+3)
=(2+3)/4
=5/4
y=(1×-3+3×1)/(1+3)
=(-3+3)/4
=0
, coordinate of C is (5/4,0)
I HOPE ITS HELP YOU DEAR,
THANKS
Answered by
1
Answer:
so (5/4, 0 ) ans...........
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