Question

Let f : R $\rightarrow$ R be a differentiable function and f(1) = 4. Then the value of $\underset{x \rightarrow 1}{lim} \int\limits^{f(x)}_4 {\frac{2t}{x-1}} \, dt$ is
(a) 8 f '(1)
(b) 4 f '(1)
(c) 2 f '(1)
(d) f '(1)

Answer 1

Answer:

Step-by-step explanation:

BRAINLIEST BRAINLIEST BRAINLIEST