Question

let n (A) =31,n (A-B)=20andn (AnB)=6.Then find n (A-B,n (B-A) and n (AUB​

Answer 1

Answer:

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Answer 2

Answer:

Given: n(A - B) =18, n(A∪B) =70, n(A ∩ B) =25

n(A∪B) = n(A - B) + n(A ∩ B) + n(B - A) 

   70 = 18 + 25 + n(B - A) 

     70 = 43 + n(B - A) 

     n(B - A) = 70 - 43 

      n(B - A) = 27 

Now n(B) = n(A ∩ B) + n(B - A) 

        n(B)  = 25 + 27 

          n(B)   = 52 

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