let n(A)= m and n(B)= n then the total number of non-empty relations that can be defined from A to B is
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Answered by
145
Answer:
We have,n(A)=m and n(B)=n
n(A×B)=n(A).n(B)=mn
Total number of relation from A to B =Number of subsets of A×B=2^mn
So,total number of non-empty relations=2^mn-1.
thank you!!
Answered by
48
Answer:
2^mn - 1
Step-by-step explanation:
The total no. of elements in AxB=n(A)xn(B)=mn
The total no. of subsets = Total no. of relations
The total n. of subsets =2^no. of sets
Total no. of relations=2^mn
This set also contains one empty set
therefore the no. of non-empty sets=2^mn - 1
Hope it helps!
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