Question

Let s be the value of d^2y/dx^2/d^2x/dy^2
at x=1, for the curve 2 y = y^x + x^y
Then the value of 2+s=..​

Answer 1

Answer:

Solution:

Put x = - 1

(1−1+1−1)n=∑3nr=0arxr⇒0=a0−a1+a2−a3+.....