let's keep velocity of a body kept at surface of a planet is you is it is projected at a speed of 200% more than the escape speed then its speed is interstellar space will be
Answers
If a body is projected with speed Vi = KVe (k>1), the final intersteller speed is (√k²-1)Ve
If a body is projected with speed Vi = KVe (k>1), the final intersteller speed is (√k²-1)Ve if Vi = KVe (k<1) directed vertically upward the maximum height from centre of earth of radius R attained by the body is r = R /1-K²
If a body is projected with speed Vi = KVe (k>1), the final intersteller speed is (√k²-1)Ve if Vi = KVe (k<1) directed vertically upward the maximum height from centre of earth of radius R attained by the body is r = R /1-K²and hence its maximum height from surface of earth is H= r-R = (R /1-K²) - R
If a body is projected with speed Vi = KVe (k>1), the final intersteller speed is (√k²-1)Ve if Vi = KVe (k<1) directed vertically upward the maximum height from centre of earth of radius R attained by the body is r = R /1-K²and hence its maximum height from surface of earth is H= r-R = (R /1-K²) - R= RK²/1-K²
If a body is projected with speed Vi = KVe (k>1), the final intersteller speed is (√k²-1)Ve if Vi = KVe (k<1) directed vertically upward the maximum height from centre of earth of radius R attained by the body is r = R /1-K²and hence its maximum height from surface of earth is H= r-R = (R /1-K²) - R= RK²/1-K²By this method now velocity is V+2V = 3V
If a body is projected with speed Vi = KVe (k>1), the final intersteller speed is (√k²-1)Ve if Vi = KVe (k<1) directed vertically upward the maximum height from centre of earth of radius R attained by the body is r = R /1-K²and hence its maximum height from surface of earth is H= r-R = (R /1-K²) - R= RK²/1-K²By this method now velocity is V+2V = 3VSo k=3
If a body is projected with speed Vi = KVe (k>1), the final intersteller speed is (√k²-1)Ve if Vi = KVe (k<1) directed vertically upward the maximum height from centre of earth of radius R attained by the body is r = R /1-K²and hence its maximum height from surface of earth is H= r-R = (R /1-K²) - R= RK²/1-K²By this method now velocity is V+2V = 3VSo k=3Finally intersteller speed = (√k²-1) viz. √8 = 2√2
Mark as Brainliest