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Let P,Q,R,S be the points where the circle touches the quadrilateral .
From a point out side of the circle the two tangents to the circle are equal.
AP = AS,BP = BQ , CR = CQ , and DR = DSAdding AP + BP + CR + DR = AS + BQ + CQ + DS AB + CD = AD + BC 6 + 4 = AD + 7AD
= 3 cm .
hope it helps
thank you
From a point out side of the circle the two tangents to the circle are equal.
AP = AS,BP = BQ , CR = CQ , and DR = DSAdding AP + BP + CR + DR = AS + BQ + CQ + DS AB + CD = AD + BC 6 + 4 = AD + 7AD
= 3 cm .
hope it helps
thank you
kartikrajput01:
what are tangent
It's used in differential calculus when you find the gradient of the tangent to a curve.
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Let P,Q,R,S be the points where the circle touches the quadrilateral .
From a point out side of the circle the two tangents to the circle are equal.
AP = AS,BP = BQ , CR = CQ , and DR = DSAdding AP + BP + CR + DR = AS + BQ + CQ + DS AB + CD = AD + BC 6 + 4 = AD + 7AD
= 3 cm .
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