let the resistance of an electrical component remains constant while the potential difference across the two ends of the component decreases to the half of its former value . what will change in the current through it.
Answers
Answered by
16
According to Ohm’s law
V = IR
⇒ I=V/R ---------- (1)
Now Potential difference is decreased to half
∴ New potential difference Vʹ=V/2
Resistance remains constant
So the new current Iʹ = Vʹ/R
= (V/2)/R
= (1/2) (V/R)
= (1/2) I = I/2
V = IR
⇒ I=V/R ---------- (1)
Now Potential difference is decreased to half
∴ New potential difference Vʹ=V/2
Resistance remains constant
So the new current Iʹ = Vʹ/R
= (V/2)/R
= (1/2) (V/R)
= (1/2) I = I/2
Divyakalyan:
Thanks
Answered by
1
♤ We know that
I = V/R
If V' = V/2
I' = V'/R
= V/2R
= 1/2
Therefore , the current will also become half of its previous value.
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