Question

Let us calculate and write the value of k for which – a will be a root the quadratic equation X² + 3ax + k = 0.

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Answer 1

Given

p(x) = x^2 +3ax +k =0

-a is a root

p(-a) =( -a)^2 +3a(-a) +k=0

a^2 -3a^2 +k =0

-2a^2 +k =0

. k= 2a^2

Hope it helps

Answer 2

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✏ANSWER✍

✒ Since '-a' is a root of the Quadratic equation

X² + 30x + k = 0

(-a)² + 3a (–a) + k = 0

Or, a² - 3a² + k = 0

Or, k - 2a² = 0

=> k = 2a² {ANS}

✌ hope it's help you✌

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