Let vector F be a force acting on a particle having position vector vector r.
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Torque is the cross product of Force Vector F and Position Vector r.
Thus T=r×F (vector form)
In a cross product, the resultant Vector (here T) is always perpendicular to both of the two vectors whose product is found.
So, here T is perpendicular to both Forward and r.
So, angle between T and F =90°
Similarly, angle between T and r=90°
Also for two vectors a and b, their dot product is
a.b = |a| |b| cos (theta) , where theta is angle between a and b
Following the two statements given above,
r.T = |r| |T| cos 90° = 0
F.T= |F| |T| cos 90° = 0
So,
r.T = 0 and F.T=0
Thus T=r×F (vector form)
In a cross product, the resultant Vector (here T) is always perpendicular to both of the two vectors whose product is found.
So, here T is perpendicular to both Forward and r.
So, angle between T and F =90°
Similarly, angle between T and r=90°
Also for two vectors a and b, their dot product is
a.b = |a| |b| cos (theta) , where theta is angle between a and b
Following the two statements given above,
r.T = |r| |T| cos 90° = 0
F.T= |F| |T| cos 90° = 0
So,
r.T = 0 and F.T=0
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