Let X and Y be a uniformly distributed random variable over the interval [0, 4] and [0, 6] respectively. If X and Y are independent events, then compute the probability, P(max(X, Y ) > 2)
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5/6 is the probability, PP(max(X, Y ) > 2)
Step-by-step explanation:
Probability of X > 2 = 2/4 = 1/2
Probability of Y > 2 = 4/6 = 2/3
PP(max(X, Y ) > 2) = P(X > 2) + P(Y > 2) - P ( X ∩ Y > 2)
= (1/2) + (2/3) - (1/2)(2/3)
= 1/2 + 2/3 - 1/3
= (3 + 4 - 2)/6
= 5/6
5/6 is the probability, PP(max(X, Y ) > 2)
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Answer:
5/6
Step-by-step explanation:
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