light of wavelenght 390×10^-19 is directed at metal electrode the potential differnce is 1.1V . determine the work finction and thresold frequency
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Work function of the metal is 4.2 eV;
Given: λ=330nm.
The energy of incident photon is given by, E=hc/λ
E = 6.63 x 10^-34 x 3 x 10⁸/ 330 x 10^-9
E=6×10^−19J or 3.79eV
E is less than work function.
Hence, no photoelectric emission will take place
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