light of wavelength 2000A falls on a metal surface of work function 4.2 ev.What is the kinetic energy in ev of fastest and slowest photoelectron emitted from the surface?
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The kinetic energy in ev of fastest and slowest photo-electron emitted from the surface is 2.0 eV.
Explanation:
We know that
Energy of photon = hc / λ
E = 6.62 x 10^34 x 3 x 10^8 / 2000 x 10^-10 J
i.e.
E = 6.62 x 10^34 x 3 x 10^8 / 2 x 10^-7 x 1.6 x 10^-19 eV
E = 6.20 eV
Energy of the fastest emitted electron.
= h ( v - vo) Where vo is the work function.
= ( 6.2 - 4. 2) eV
K.E = 2.0 eV
The metal electron have an energy distribution, the minimum energy in this distribution being zero, the energy of slowest photo electrons is also zero.
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