Math, asked by ritikkadhao, 4 months ago

lim x exten to 0 tanx-x/xsquaretqnx

Answers

Answered by sm9775413

0

Answer:

limx→0x2tanxtanx−x

=limx→0x2sec2x+2xtanxsec2x−1

∵ Applying L' Hospital's Rule.

=limx→02x2sec2xtanx+2csec2x+2xsec2x+2tanx2sec2xtanx

=limx→02x2(2sec4x+4sec2xtanx)+4xsec2xtanx+4sec2x+8xsec2xtanx+2sec2x2sec2x+4sec2xtanx

=limx→02x2(2sec2x+4sec2xtanx)+12xsec

Answered by sudhirpatliputra6

1

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