Question

lim x tend to 1 log x/x^2-1​

Answer 1

Step-by-step explanation:

Use l'Hospital's Rule twice:

limx→0 1/x - ln(1+x)/x²

= lim (x - ln(1+x))/x²

= lim (1- 1/(x+1) )/2x

= lim (x/(2x+2x²))

= lim (1/(2+4x))

= 1/2