Math, asked by montisha9196, 1 year ago

Lim x tends to 3 x^5- 243/x^2-9


dhruvsh: what's the x tending to?
montisha9196: Limit X tends to 3

Answers

Answered by mysticd
6
Solution :

Lim ( x ->3 )[ (x^5 - 3^5 )/(x² - 3²) ]

=Lim (x->3){[(x^5-3^5)/(x-3)]/[(x²-3²)/(x-3)}

= [ 5* 3^5-1 ]/[ 2*3^2-1 ]

= [ 5*3⁴ ]/( 2*3 )

= ( 5/2 ) * 3³

= 137/2

••••

montisha9196: In third step ??
mysticd: Lim( x-> a) [ xⁿ - aⁿ ]/( x - a )
mysticd: = n * a^n-1
montisha9196: thanks
Similar questions