Question

Lin had two small baking pans, each shaped like a rectangular prism. For each question, explain or show your reasoning.

PART A
Lin lines the bottom of her first pan with aluminum foil. The area of the rectangular piece of foil is 11\frac{1}{4} square inches. Its length is 4\frac{1}{2} inches.



What is the width of the foil?



Enter your answer in the box below.

inches
PART B
Show your reasoning or explain how you got your answer in Part A.


PART C
Lin’s second pan has a length of \frac{8}{3} inches, a width of \frac{15}{4} inches, and a height of \frac{3}{2} inches.

What is the volume of the second pan?

Enter your answer in the box below.

cubic inches
PART D
Show your reasoning or explain how you got your answer in Part C.

Enter your response here

Answer 1

Given:

PART A

Lin lines the bottom of her first pan with aluminium foil. The area of the rectangular piece of foil is 11\frac{1}{4} square inches. Its length is 4\frac{1}{2} inches.

PART C

Lin’s second pan has a length of \frac{8}{3} inches, a width of \frac{15}{4} inches, and a height of \frac{3}{2} inches.

To find:

What is the width of the foil? Show your reasoning or explain how you got your answer in Part A.

What is the volume of the second pan? Show your reasoning or explain how you got your answer in Part C.

Solution:

Finding the width of the foil-lined in the first pan:

Let "w" inches represents the width of the foil.

The length of the aluminium foil = $4\frac{1}{2} \:inches = \frac{9}{2} \:inches$

The area of the rectangular foil = $11\frac{1}{4} \:inches = \frac{45}{4} \:inches$

We know,

$\boxed{\bold{Area \:of\:a\:rectangle = length \times width}}$

∴ The width of the foil = $\frac{Area }{length} = \frac{\frac{45}{4} }{\frac{9}{2} } = \frac{45}{4} \times \frac{2}{9} = \frac{5}{2} \:inches$

Thus, the width of the foil is → $\underline{\bold{\frac{5}{2}\:inches }}$

Finding the volume of the second pan:

The dimensions of the second pan:

Length = $\frac{8}{3} \:inches$

Width = $\frac{15}{4} \:inches$

Height = $\frac{3}{2}\:inches$

We know,

$\boxed{\bold{Volume \:of\:a\:cuboid = length \times width\times height }}$

∴ The volume of the cuboidal second pan is,

= $\frac{8}{3} \times \frac{15}{4} \times \frac{3}{2}$

= $\bold{15\: cubic\: inches }$

Thus, the volume of the second pan is → $\underline{\bold{15 \:cubic\:inches }}$.

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Answer 2

Answer:I need help on that two

Step-by-step explanation:

Lin has two small baking pans, each shaped like a rectangular prism. Explain or show your reasoning.

b. Lin’s second pan has a length of

inches, a width of

inches, and a height of

inches.

What is the volume of the second pan? ​

[ ]cubic inches