Question

Line l is the bisector of an angle A and B is any point on l. BP and BQ are perpendiculars from B to the arms of angle A. Show that : 1. Triangle APB congruent to triangle AQB 2. BP equals to BQ or B is equidistant from the arms of angle A

Answer 1

APB = AQB
PAB = QAB
AB = AB (common)
APB = AQB (AAS)
BP = BQ (CPCT)

Answer 2

Answer:Given: line L is bisector of angle A and B is any point on L. BP and BQ are perpendicular from B to arm of angle A

Step-by-step explanation:1) In triangle APB and AQB

angle BAP=BAQ

AB=AB(COMMON)

ANGLE BPA=BQA

2) TRIANGLE APB IS CONGRANT to TRIANGLE AQB( AAS)

BP=BQ (CPCT)