Question

linear equation two variable
solve this question..

Answer 1

Heya mate ⭐

let the original speed of the aeroplane be x km /h.

then ,A/Q :-
=> 600/(x-200) - 600/x = 1/2
=> [600 x - 600 (x-200)]/ {x(x-200)} = 1/2

=>$x {}^{2} - 200x \: - 240000 = 0 \\=> x ^{2} - 600x \: + 400x - 240000 = 0 \\ =>x(x - 600) + 400(x \: - 600) = 0 \\=> (x \: + 400)(x \: - 600) = 0$
therfore , x = -400 or x= 600

hence the original speed = 600 km/h

therefore the duration of the flight is =600/600 h = 1h.

$hope \: it \: helps \: you$ !!

Answer 2

let the original speed be xkm/h
according to the question
600/(x-200)-600/x=1/2
(600x-600(x-200))/(x(x-200)=1/2
x^2 -200x-240000=0
x^2-600x+400x-240000=0
x(x-600)+400(x-400)=0
therefore x =-400or 600
original speed = 600
duration=600/600=1h