Question

LINEAR EQUATIONS IN ONE V
xaraple 15: Arjun is twice as old as Shriya. Five years ago his age was three times
hriya's age. Find their present ages.​

Answer 1

Answer:

Arjuns age is 20 years and Shriya's age is 10 years .

Step-by-step explanation:

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Answer 2

AnswEr :

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• The present age of Shriya and Arjun = 10 years and 20 years respectively.

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Step-by-step explanation :

Given: Arjun is twice as old as Shriya. Five years ago his age was three times heiya's age.

We need to find their present age.

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☯ Let us consider that the Shriya age is x years.

And, the Arjun present age would be.

$\sf{:\implies Arjun = 2x}$

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Five years ago,

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→ Shriya age = (x - 5) years.

→ Ajay age = (2x - 5) years.

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According to the given question,

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As it is given that, Five years ago his age was three times Shriya's age.

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Therefore,

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$\sf{:\implies 2x - 5 = 3(x - 5)}$

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$\sf{:\implies 2x - 5 = 3x - 15}$

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$\sf{:\implies 2x - 3x = 15 - 5}$

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$\sf{:\implies x = 15 - 5}$

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$\sf{:\implies \boxed{ \frak{ \pink{x = 10}}}}$

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Now,

• Shriya present age, x = 10 years.
• Arjun present age, 2x = 2 × 10 = 20 years.

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Hence, The present age of Shriya and Arjun is 10 years and 20 years respectively.