Question

locate root 3 on the number line with construction

Answer 1

(1) Construct BD of unit length perpendicular to OB.
(2) Then using the pythagorus theorem, we see that OD =
$\sqrt{( \sqrt{2) {}^{2} } + 1 {}^{2} } = \sqrt{3}$
(3) Using a compass,with centre O and radius OD,draw an arc whuch intersects the number line at the point Q.
$(4) \: then \: q \: corresponds \: to \: \sqrt{3}$


Hope Helps^_^

Answer 2

⦁First construct the BD of unit length perpendicular to OB.

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⦁Then apply the Pythagoras theorem $\rm{OD = \sqrt{(\sqrt{2})^{2} + 1^{2} = \sqrt{3}}}$

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⦁We can locate $\rm{\sqrt{3}}$ on number line by using a compass.

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⦁We know that, O is the center and radius OD. Now let's draw an arc which intersects the number line at the point Q.

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⦁Therefore, now the point Q = $\rm{\sqrt{3}}$