Locate square root of 2 on the real number line
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Answer:
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Step-by-step explanation:
1. draw a number line.
2. draw 2 perpendicular lines from 0 & 1.
3. draw arcs with centers 0 and 1 respectively to the perpendiculars such that they intersects on the perpendiculars with radius of distance from 0 to 1
4. now join the intersection points and name them as A and B.
5. now join 0B and draw an arc with center 0 and radius 0B to the number line.
6. the intersection point is the root of 2.
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Answer:
- Firstly let's take a number line.
- Let 0 be O and 1 be A. OA be the base.
- Let A - B be the height with 1 unit.
- AB perpendicular to AO.
- Let's join O and B.
Therefore, now both AB, OB are equal to 1 unit.
Now using Pythagorean theorem:
⇢ OB² = OA² + AB²
⇢ 1² + 1²
⇢ 2
Now, taking square roots on both the sides:
⇢ OB = √2
Now, here OB is equal to √2 but we need this √2 here on number line.
So, now it's time to take the geometric equipments.
- Take the vertex point on point O.
- Now cut an arc in OB on the number.
- The new point on the number like would be C.
- Taking the arc we can replace the measure of OB to OC on the number line.
Therefore, OC = √2.
- You can draw these measures using the above steps
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