log_1-2x(6x^2-5x+1) - log_1-3x(4x^2-4x+1)
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It is in the form of log a-log b
log a-log b = loga/b
so,1-2x(6x²-5x+1)/1-3x(4x²-4x+1)
= 1-2x(6x²-5x+1)/1-3x(4x²-4x+1)
= 6x²-5x+1-12x³+10x²-2x/4x²-4x+1-12x³+12x²-3x
=16x²-12x³-7x+1/16x²-12x³-7x+1
= 1
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