Question

log(1^(3)+2^(3)+3^(3)......+n^(3))=...​

Answer 1

Answer:

Step-by-step explanation:

1^3+2^3+3^3+-----=n^2(n+1)^2/4

log(n^2(n+2)^2/4)

=log((n(n+1)/2)^2)

=2log(n(n+1)/2)