Question

Log^2(x)-3logx=log(x)^2 -4

Answer 1

Answer:

If I guess the question is log2x-3logx= logx^2-4

then at log base 2

log2x - log x^3 = log x^2 - 4log2

=> log (2x. x^3) = log x^2 - log2^4

=> log (2x^4) = log ((x^2)/16)

=> 2x^4 = (x^2)/16

=> x^2 = 1/32

=> x = 1/(4√2) or -1/(4√2)