Question

log(7x+3)-log(x-3)=1​

Answer 1

Answer:

11

Step-by-step explanation:

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Answer 2

The value of x is 11.

Step-by-step explanation:

The expression is:

$\log_{10}(7x+3)-\log_{10}(x-3)=1$

**Assuming the base as 10.

Compute the value of x as follows:

$\log_{10}(7x+3)-\log_{10}(x-3)=1$

                       $\log_{10}[\frac{(7x+3)}{(x-3)}]=1$

                                 $\frac{(7x+3)}{(x-3)}=10^{1}$

                                $7x+3=10(x-3)\\7x+3=10x-30$

                            $\\7x-10x=-30-3$

                                   $-3x=-33$

                                       $x=11$

Thus, the value of x is 11.

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